4y^2+4y=(143-119)+44y+8y

Solution for 4y^2+4y=(143-119)+44y+8y equation:

4y^2+4y=(143-119)+44y+8y

We move all terms to the left:

4y^2+4y-((143-119)+44y+8y)=0

We add all the numbers together, and all the variables

4y^2+4y-(24+44y+8y)=0

We get rid of parentheses

4y^2+4y-44y-8y-24=0

We add all the numbers together, and all the variables

4y^2-48y-24=0

a = 4; b = -48; c = -24;
Δ = b2-4ac
Δ = -482-4·4·(-24)
Δ = 2688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2688}=\sqrt{64*42}=\sqrt{64}*\sqrt{42}=8\sqrt{42}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-8\sqrt{42}}{2*4}=\frac{48-8\sqrt{42}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+8\sqrt{42}}{2*4}=\frac{48+8\sqrt{42}}{8}
$